Ta có: \(n_{Na_2O}=\dfrac{24,8}{62}=0,4\left(mol\right)\)
\(n_{HNO_3}=\dfrac{50,4}{63}=0,8\left(mol\right)\)
PT: \(Na_2O+2HNO_3\rightarrow2NaNO_3+H_2O\)
____0,4_____0,8_________0,8 (mol)
→ Pư vừa đủ.
\(\Rightarrow m_{NaNO_3}=0,8.85=68\left(g\right)\)
Bạn tham khảo nhé!