Question

Cho 2,25g hh gồm 2KL hoá trị 2 vào dd HCL thu được 3,36l hidro ở dktc 1, Tìm 2KL biết be=9 mg=24 ca=40 sr=87 ba=137 2, tìm kl muối clorua

Answer 1

\(n_{H_2}=\dfrac{3.36}{22.4}=0.15\left(mol\right)\)

\(\overline{M}+2HCl\rightarrow\overline{M}Cl_2+H_2\)

\(0.15..............................0.15\)

\(M_{\overline{M}}=\dfrac{2.25}{0.15}=15\left(\dfrac{g}{mol}\right)\)

\(A< 15< B\)\(\)

\(A=9\Rightarrow A:Be\)

\(B=24\Rightarrow B:Mg\)

\(n_{HCl}=2n_{H_2}=2\cdot0.15=0.3\left(mol\right)\)

\(BTKL:\)

\(m_{KL}+m_{HCl}=m_M+m_{H_2}\)

\(\Rightarrow m_M=2.25+0.3\cdot36.5-0.15\cdot2=12.9\left(g\right)\)