a, \(CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O\)
b, \(n_{NaOH}=\dfrac{200.10\%}{40}=0,5\left(mol\right)\)
Theo PT: \(n_{CH_3COO}=n_{CH_3COONa}=n_{NaOH}=0,5\left(mol\right)\)
\(\Rightarrow m_{CH_3COONa}=0,5.82=41\left(g\right)\)
c, \(C\%_{CH_3COONa}=\dfrac{41}{200+200}.100\%=10,25\%\)
d, \(CH_3COOH+C_2H_5OH⇌CH_3COOC_2H_5\) (đk: to, H2SO4 đặc)
Theo PT: \(n_{CH_3COOC_2H_5\left(LT\right)}=n_{CH_3COOH}=0,5\left(mol\right)\)
Mà: H = 90%
\(\Rightarrow m_{CH_3COOC_2H_5}=0,5.88.90\%=39,6\left(g\right)\)