Theo đề bài ta có \
\(\hept{\begin{cases}a>b;c>d\\ab=cd\\a>c\end{cases}}\)
\(\Rightarrow c>d>b\)(vì nếu \(d\le b\)thì \(ab>cd\))
Ta cần chứng minh
\(a+b>c+d\)
\(\Leftrightarrow\frac{cd}{b}+b>c+d\)
\(\Leftrightarrow cd+b^2>cb+db\)
\(\Leftrightarrow\left(cd-cb\right)+\left(b^2-db\right)>0\)
\(\Leftrightarrow\left(d-b\right)\left(c-b\right)>0\)(đúng)
\(\Rightarrow\)ĐPCM
Tinh cac kich thuoc cua hinh chu nhat co dien tich 40cm2 , biet rang neu tang moi kich thuoc them 3cm thi dien tich tang them 48cm2
mot hinh chu nhat co chieu rong bang 2/3 chieu dai. Neu bot moi canh 5cm thi duoc mot hinh chu nhat moi co dien tich bang 21/25 dien tich hinh chu nhat ban dau. Tinh cac kich thuoc cua hinh chu nhat ban dau
Tim so tu nhien co 2 chu so biet rang chu so hang chuc lon hon chu so hang don vi la 2 va so do lon hon tong cac binh phuong cac chu so cua no la 1.
1 manh vuon hinh chu Nhat co chieu dai Lon hon chieu ring 15 m. neu giam chieu dai 2m va tang chieu tong 3m Thi S vuon tang 44m^2. Tinh S manh vuon
Mot thua ruong hinh thang co do dai day lon la 21m va dai hon canh day be la 8,2m. Neu mo rong day lon them 7m thi dien tich tang them 56m2. Tinh dien tich thua ruong do
AI BIET CHI MINH VOI
Chung minh rang 1 hinh vuong co the chia thanh mot so bat ki lon hon 5 hinh vuong nhung khong thê chia thanh dung 5 hinh vuong
cho mot hing chu nhat . biet cac kich thuoc va tich cac kich thuoc cua no lan luot bang 60m va 875 m2 . tinh cac kich thuoc cua hinh chu nhat do
tim tat ca cac so tu nhien có 2 chu so biet rang chu so hang don vi nho hon chu so hang chuc la 2 va tich cua chu so do cua no luon lon hon tong cua hai chu so cua nó la 34 don vi
Cho 2 duong tron (O;R) va (O';R') tiep xuc ngoai tai A (R > R'). Ve day AM cua duong tron (O) va day AN cua duong tron (O') sao cho AM vuong goc AN. Goi BC la mot tiep tuyen chung ngoai cua 2 duong tron (O) va(O') voi B thuoc (O) va C thuoc (O').
a) CMR 3 duong thang MN, BC va OO' dong quy.
b) Xac dinh vi tri cua M va N de tu giac MNOO' co dien tich lon nhat. Tinh gia tri lon nhat do.
