a, \(n_{SO_2}=0,15 (mol)\)
Đặt \(n_{Ag}=x(mol)\\ n_{Cu}=y( mol)\)
\( 2Ag+2H_2SO_4\to Ag_2SO_4+2H_2O+SO_2\\ Cu+2H_2SO_4\to CuSO_4+2H_2O+SO_2\)
\(\Rightarrow\)\(\left\{{}\begin{matrix}108x+64y=17,2\\0,5X+Y=0,15\end{matrix}\right.\)
\(\Rightarrow\)\(\left\{{}\begin{matrix}X=0,1\\Y=0,1\end{matrix}\right.\)
\(m_{Ag}=0,1.108=10,8(g)\\ m_{Cu}=0,1.64=6,4(g)\)
\(\% m_{Ag}=10,8:17,2.100\%=62,79\%\\ \%m_{Cu}=100\%-62,79\%=37,21\%\)
b, \(n_{H_2SO_4}=0,3(mol)\\ m_{H_2SO_4}=0,3.98=29,4(g)\\ V=29,4:96\%:1,84=16,64ml\)
a, nSO2=0,15(mol)
Đặt nAg=x(mol)nCu=y(mol)
2Ag+2H2SO4→Ag2SO4+2H2O+SO2
Cu+2H2SO4→CuSO4+2H2O+SO2
⇒ {108x+64y=17,2 ; 0,5X+Y=0,15
⇒ {X=0,1 ; Y=0,1
mAg=0,1.108=10,8(g)
mCu=0,1.64=6,4(g)
%mAg=10,8:17,2.100%=62,79%
%mCu=100%−62,79%=37,21%
b, nH2SO4=0,3(mol)
mH2SO4=0,3.98=29,4(g)
V=29,4:96%:1,84=16,64ml