`Zn + 2HCl -> ZnCl_2 + H_2↑`
`0,2` `0,4` `0,2` `0,2` `(mol)`
`a) n_[Zn] = 13 / 65 = 0,2 (mol)`
`-> V_[H_2] = 0,2 . 22,4 = 4,48 (l)`
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`b) m_[dd HCl] = [ 0,4 . 36,5 ] / [7,3] . 100 = 200 (g)`
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`c) C%_[ZnCl_2] = [ 0,2 . 136 ] / [ 200 + 13 - 0,2 . 2 ] . 100 ~~ 12,79%`
Zn+2HCl→ZnCl2+H2↑Zn+2HCl→ZnCl2+H2↑
0,20,2 0,40,4 0,20,2 0,20,2 (mol)(mol)
a)nZn=1365=0,2(mol)a)nZn=1365=0,2(mol)
→VH2=0,2.22,4=4,48(l)→VH2=0,2.22,4=4,48(l)
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b)mddHCl=0,4.36,57,3.100=200(g)b)mddHCl=0,4.36,57,3.100=200(g)
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c)C%ZnCl2=0,2.136200+13−0,2.2.100≈12,79%.
