\(n_{HCl}=0,3.2=0,6\left(mol\right)\)
PT: \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
a, \(n_{Al}=\dfrac{1}{3}n_{HCl}=0,2\left(mol\right)\)
\(\Rightarrow m_{Al}=0,2.27=5,4\left(g\right)\)
b, \(n_{H_2}=\dfrac{1}{2}n_{HCl}=0,3\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,3.22,4=6,72\left(l\right)\)