\(?1\\ a,=\dfrac{\sqrt{4}\sqrt{5}}{5}=\dfrac{2\sqrt{5}}{5}\\ b,=\dfrac{\sqrt{3}}{5\sqrt{5}}=\dfrac{\sqrt{15}}{10}\\ c,=\dfrac{\sqrt{3}}{a\sqrt{2a}}=\dfrac{\sqrt{6a}}{2a^2}\\ 2,\\ a,=\dfrac{10\sqrt{2}}{24}=\dfrac{5\sqrt{2}}{12}\\ b,=\dfrac{3\left(\sqrt{3}-1\right)}{3-1}=\dfrac{3\sqrt{3}-3}{2}\\ c,=\dfrac{2\left(\sqrt{6}+\sqrt{5}\right)}{6-5}=2\sqrt{6}+2\sqrt{5}\)