Question

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Answer 1

\(\dfrac{9x-0,7}{4}-\dfrac{5x-1,5}{7}=\dfrac{7x-1,1}{3}-\dfrac{5\left(0,4-2x\right)}{6}\)

=>\(\dfrac{7\left(9x-0,7\right)-4\left(5x-1,5\right)}{28}=\dfrac{2\left(7x-1,1\right)-5\left(0,4-2x\right)}{6}\)

=>\(\dfrac{63x-4,9-20x+6}{28}=\dfrac{14x-2,2-2+10x}{6}\)

=>\(\dfrac{43x+1,1}{28}=\dfrac{24x-4,2}{6}\)

=>\(28\left(24x-4,2\right)=6\left(43x+1,1\right)\)

=>672x-117,6=258x+6,6

=>414x=124,2

=>\(x=124,2:414=0,3\)