Câu 94: B
Câu 95: \(A=\left(-\dfrac{b}{2a};-\dfrac{b^2-4ac}{4a}\right)\)
\(\Leftrightarrow A\left(\dfrac{-2}{2\cdot\left(-1\right)};\dfrac{-\left(2^2-4\cdot\left(-1\right)\cdot3\right)}{4\cdot\left(-1\right)}\right)\)
\(\Leftrightarrow A\left(1;4\right)\)