a) \(n_{Cl_2}=\dfrac{V}{24,79}=\dfrac{6,1975}{24,79}=0,25\left(mol\right)\)
\(m_{Cl_2}=n.M=0,25.71=17,75\left(g\right)\)
b) \(n_{CO_2}=\dfrac{m}{M}=\dfrac{8,8}{12+2.16}=0,2\left(mol\right)\)
\(n_{CO_2}=\dfrac{V}{24,79}\Rightarrow V=n_{CO_2}.24,79=0,2.24,79=4,958\left(l\right)\)