ĐKXĐ : \(x^2-3x+3\ge0\Leftrightarrow x\inℝ\)
Ta có : \(\sqrt{x^2-3x+3}=2x-1\)
\(\Leftrightarrow x^2-3x+3=\left(2x-1\right)^2\) (với \(2x-1\ge0\Leftrightarrow x\ge\dfrac{1}{2}\left(^∗\right)\)
\(\Leftrightarrow3x^2-x-2=0\)
\(\Leftrightarrow\left(x-1\right).\left(3x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\left(tm\right)\\x=-\dfrac{2}{3}\left(\text{loại}\right)\end{matrix}\right.\)
Tập nghiệm S = {1}
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren:
x^2-3x=(2x-1)^2
=>x^2-3x=2x^2-2.2x+1
=>x^2-3x-2x^2+4x-1=0
=>-x^2+x-1
=> x=?, x=?
thay x =? vao pt tren:
thay x =? vao pt tren: