Question

Cần phải thêm bao nhiêu nước vào 2 lít dung dịch NaOH 40%, d = 1,43 g/ml để có dung dịch kiềm 10%.

Answer 1

\(m_{NaOH}=\dfrac{2000,1,43.40\%}{100\%}=1144g\\ m_{ddNaOH\left(10\%\right)}=\dfrac{1144}{10\%}\cdot100\%=11440g\\ V_{H_2O.thêm}=m_{H_2O.thêm}=11440-2000.1,43=8580ml\)

Answer 2

mNaOH=2000,1,43.40%100%=1144gmddNaOH(10%)=114410%⋅100%=11440gVH2O.thêm=mH2O.thêm=11440−2000.1,43=8580ml