b: \(=\dfrac{x+1}{2\left(x-1\right)}+\dfrac{-2x^2+3}{3\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{3x^2+6x+3-4x^2+6}{6\left(x-1\right)\left(x+1\right)}=\dfrac{-x^2+6x+9}{6\left(x-1\right)\left(x+1\right)}\)
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