v: \(\dfrac{26}{-37}< 0\)
\(0< \dfrac{11}{19}\)
Do đó: \(\dfrac{26}{-37}< \dfrac{11}{19}\)
x: \(\dfrac{-7}{30}=\dfrac{-7\cdot2}{30\cdot2}=\dfrac{-14}{60}\)
\(\dfrac{13}{-20}=\dfrac{-13}{20}=\dfrac{-13\cdot3}{20\cdot3}=\dfrac{-39}{60}\)
mà -14>-39
nên \(-\dfrac{7}{30}< \dfrac{13}{-20}\)
y: \(-\dfrac{12}{16}=\dfrac{-12\cdot3}{16\cdot3}=\dfrac{-36}{48}\)
\(\dfrac{-16}{48}=\dfrac{-16}{48}\)
mà -36<-16
nên \(\dfrac{-12}{16}< -\dfrac{16}{48}\)
z: \(\dfrac{-18}{-72}=\dfrac{1}{4}>0\)
\(0>-\dfrac{5}{20}\)
Do đó: \(\dfrac{-18}{-72}>-\dfrac{5}{20}\)
z1: \(\dfrac{-36}{90}=\dfrac{-2}{5};\dfrac{-15}{25}=\dfrac{-3}{5}\)
mà -2>-3
nên \(\dfrac{-36}{90}>\dfrac{-15}{25}\)
z2: \(\dfrac{-32}{48}=\dfrac{-2}{3}=\dfrac{-4}{6}\)
\(\dfrac{-6}{12}=\dfrac{-1}{2}=\dfrac{-3}{6}\)
mà -4<-3
nên \(-\dfrac{32}{48}< -\dfrac{6}{12}\)
z3: \(\dfrac{-20}{-45}=\dfrac{4}{9}=\dfrac{40}{90}\)
\(\dfrac{35}{150}=\dfrac{7}{30}=\dfrac{21}{90}\)
mà 40>21
nên \(\dfrac{-20}{-45}>\dfrac{35}{150}\)
