Question

Cần gấp ạ tks bạn giải

Answer 1

Bài 27:

a. $4=2.2=2.\sqrt{4}>2.\sqrt{3}$

b. $-\sqrt{5}< -\sqrt{4}=-2$

 

Answer 2

Bài 28:

a. 

\((\sqrt{2}+\sqrt{3})^2=5+2\sqrt{6}=5+2\sqrt{\frac{24}{4}}< 5+2\sqrt{\frac{25}{4}}=5+2.\frac{5}{2}=10\)

$\Rightarrow \sqrt{2}+\sqrt{3}< \sqrt{10}$

b.

\((\sqrt{3}+2)^2=7+4\sqrt{3}\)

\((\sqrt{2}+\sqrt{6})^2=8+4\sqrt{3}\)

Mà $7+4\sqrt{3}< 8+4\sqrt{3}$

$\Rightarrow (\sqrt{3}+2)^2< (\sqrt{2}+\sqrt{6})^2$
$\Rightarrow \sqrt{3}+2< \sqrt{2}+\sqrt{6}$

c.

$\sqrt{15}.\sqrt{17}=\sqrt{15.17}=\sqrt{(16-1)(16+1)}=\sqrt{16^2-1}$

$<\sqrt{16^2}=16$

d.

\((\sqrt{15}+\sqrt{17})^2=32+2\sqrt{15.17}< 32+2.16=64\) (theo kq phần c)

$\Rightarrow \sqrt{15}+\sqrt{17}< \sqrt{64}=8$