\(log_m\left(7\right)-log_m\left(5-y\right)=log_m\left(6\right)+log_m\left(4\right)\)
\(\Leftrightarrow log_m\left(\dfrac{7}{5-y}\right)=log_m\left(24\right)\)
\(\Leftrightarrow\dfrac{7}{5-y}=24\)
\(\Leftrightarrow y=\dfrac{113}{24}\)
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