\(c,=\dfrac{101}{18}+\left(\dfrac{21}{5}-\dfrac{29}{9}\right)-\left(\dfrac{196}{15}-\dfrac{2}{3}+\dfrac{7}{18}\right)\\ =\dfrac{101}{18}+\dfrac{21}{5}-\dfrac{29}{9}-\dfrac{196}{15}+\dfrac{2}{3}-\dfrac{7}{18}\\ =\dfrac{47}{9}+\dfrac{21}{5}-\dfrac{29}{9}-\dfrac{196}{15}+\dfrac{2}{3}\\ =2+\dfrac{21.3-196+2.5}{15}\\ =2-\dfrac{41}{5}\\ =\dfrac{10-41}{5}\\ =-\dfrac{31}{5}\)