Question

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Answer 1

\(=\dfrac{45}{19}-\left(\dfrac{1}{2}+\left(\dfrac{1}{3}+4\right)^{-1}\right)^{-1}\\ =\dfrac{45}{19}-\left(\dfrac{1}{2}+\left(\dfrac{13}{4}\right)^{-1}\right)^{-1}\\ =\dfrac{45}{19}-\left(\dfrac{1}{2}+\dfrac{4}{13}\right)^{-1}\\ =\dfrac{45}{19}-\left(\dfrac{21}{26}\right)^{-1}=\dfrac{45}{19}-\dfrac{26}{21}=\dfrac{451}{399}\)