a: Ta có: \(A=x^2-20x+5\)
\(=\left(x-10\right)^2-95\ge-95\forall x\)
Dấu '=' xảy ra khi x=10
b: Ta có: \(A=x^2-5x-12\)
\(=x^2-2\cdot x\cdot\dfrac{5}{2}+\dfrac{25}{4}-\dfrac{73}{4}\)
\(=\left(x-\dfrac{5}{2}\right)^2-\dfrac{73}{4}\ge-\dfrac{73}{4}\forall x\)
Dấu '=' xảy ra khi \(x=\dfrac{5}{2}\)