\(=\dfrac{4}{3}\left(\dfrac{3}{9.12}+\dfrac{3}{12.15}+...+\dfrac{3}{252.255}\right)\)
\(=\dfrac{4}{3}\left(\dfrac{1}{9}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{15}+...+\dfrac{1}{252}-\dfrac{1}{255}\right)\)
\(=\dfrac{4}{3}\left(\dfrac{1}{9}-\dfrac{1}{255}\right)=\dfrac{4}{3}\times\dfrac{82}{765}=\dfrac{328}{2295}\)