\(\dfrac{\left(x-2\right)}{3}\)= \(\dfrac{\left(x+1\right)}{4}\)
=> (x - 2) . 4 = (x +1) . 3
=> 4x - 8 = 3x + 3
=> 4x - 3x = 3 + 8
=> x = 11
\(\dfrac{\left(x-2\right)}{3}=\dfrac{\left(x+1\right)}{4}\)
\(\Leftrightarrow\dfrac{4x-8}{12}=\dfrac{3x+3}{12}\)
\(\Leftrightarrow4x-8=3x+3\)
\(\Leftrightarrow4x-3x=3+8\)
\(\Leftrightarrow x=11\)
=> (x - 2) . 4 = (x +1) . 3
=> 4x - 8 = 3x + 3
=> 4x - 3x = 3 + 8
=> x = 11
Vậy phương trình có tập nghiệm S=(2)