Các câu hỏi tương tự
1.Tính C=\(\frac{\left(1+\frac{1999}{1}\right)\left(1+\frac{1999}{2}\right)\left(1+\frac{1999}{3}\right)...\left(1+\frac{1999}{1000}\right)}{\left(1+\frac{1000}{1}\right)\left(1+\frac{1000}{2}\right)\left(1+\frac{1000}{3}\right)...\left(1+\frac{1000}{1999}\right)}\)
A = (1 + 1999/1)(1 + 1999/2)......(1 + 1999/1000)
B = ( 1 + 1000/1)(1 + 1000/2)......(1 + 1000/1999)
Tính A/B
\(A=\frac{\left(1+\frac{1999}{1}\right)\left(1+\frac{1999}{2}\right)\left(1+\frac{1999}{3}\right)...\left(1+\frac{1999}{1000}\right)}{\left(1+\frac{1000}{1}\right)\left(1+\frac{1000}{2}\right)\left(1+\frac{1000}{3}\right)...\left(1+\frac{1000}{1999}\right)}\)
hỏi a = ?
HELP MEEE!!!
A = (1 + 1999/1)(1 + 1999/2)......(1 + 1999/1000)
B = ( 1 + 1000/1)(1 + 1000/2)......(1 + 1000/1999)
Tính A/B
Tính :
C= \(\frac{\left(1+\frac{1999}{1}\right)\left(1+\frac{1999}{2}\right)...\left(1+\frac{1999}{1000}\right)}{\left(1+\frac{1000}{2}\right)\left(1+\frac{1000}{2}\right)...\left(1+\frac{1000}{1999}\right)}\)
CMR 1+1/2+1/3+.......+1/2^1999 >1000
cmr :1+1/2+1/3+...+1/2 mũ 1999>1000
Câu hỏi: CMR: 1+1/2+1/3+....1/2^1999 >1000
CHứng minh rằng 1 + \(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^{1999}}>1000\)