\(ab\) là \(\overline{ab}\) hay \(a\times b\)???
\(\overline{ab}+\overline{ba}=99\\ \Rightarrow10a+b+10b+a=99\\ \Rightarrow11a+11b=99\\ \Rightarrow11\left(a+b\right)=99\\ \Rightarrow a+b=99:11=9\)
Mà \(a-b=1\)
Vậy \(a=\left(11+1\right):2=6;b=\left(11-1\right):2=5\)