\(=\left(\sqrt{5}-1-5\right)\cdot\left(\frac{\sqrt{5}\left(1+\sqrt{5}\right)}{1+\sqrt{5}}+6\right)=\left(\sqrt{5}-6\right)\left(\sqrt{5}+6\right)=5-36=-31\)
\(=\left(\sqrt{5}-1-5\right)\cdot\left(\frac{\sqrt{5}\left(1+\sqrt{5}\right)}{1+\sqrt{5}}+6\right)=\left(\sqrt{5}-6\right)\left(\sqrt{5}+6\right)=5-36=-31\)
Tính
a/\(\left(\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}-\frac{\sqrt{216}}{3}\right).\frac{1}{\sqrt{6}}\)
b/\(\left(\frac{5}{4-\sqrt{11}}+\frac{1}{3+\sqrt{7}}-\frac{6}{\sqrt{7}-2}-\frac{\sqrt{7}-5}{2}\right)\)
c/\(\left(\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}+\frac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{7}-\sqrt{5}}\)
d/\(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}+\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}-\frac{\sqrt{5}+1}{\sqrt{5}-1}\)
giúp mik vs
trục căn thức ở mẫu
\(\frac{1\sqrt{2}}{\sqrt{2}.\sqrt{2}}\) \(\frac{1\sqrt[]{3}}{\sqrt{3}.\sqrt{3}}\)\(\frac{2\sqrt{5}-5}{\sqrt{5}-2}\)\(\frac{6-2\sqrt{6}}{2-\sqrt{6}}\)\(\frac{5\sqrt{6}-6\sqrt{5}}{\sqrt{5}-\sqrt{6}}\)\(\frac{1}{\sqrt{5}-1}\)\(\frac{1}{4-2\sqrt{a}+a}\)\(\frac{1}{b-2\sqrt{b}+4}\)\(\frac{1}{b-3\sqrt{b}+9}\)
a) \(\frac{1}{2+\sqrt{3}}+\frac{\sqrt{2}}{\sqrt{6}}-\frac{2}{3+\sqrt{3}}\)
b) \(\frac{\sqrt{5}-2}{5+2\sqrt{5}}-\frac{1}{2+\sqrt{5}}+\frac{1}{\sqrt{5}}\)
c)\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
d)\(\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
e)\(\sqrt{\frac{3-\sqrt{5}}{3+\sqrt{5}}}-\sqrt{\frac{3+\sqrt{5}}{3-\sqrt{5}}}\)
f)\(\left(\frac{1}{3-\sqrt{5}}-\frac{1}{3+\sqrt{5}}\right):\frac{5-\sqrt{5}}{\sqrt{5}-1}\)
thực hiện phép tính: a)\(\left(\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}+\frac{\sqrt{15}+\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{7}-\sqrt{5}}\)
b)\(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}+\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}+\frac{\sqrt{5}+1}{\sqrt{5}-1}\)
c)\(2\sqrt{18\sqrt{3}}-2\sqrt{5\sqrt{3}}-3\sqrt{5\sqrt{48}}\)
d)\(\left(2\sqrt{5}+\sqrt{12}\right)\left(\sqrt{3}-\sqrt{5}\right)\)
e)\(\sqrt{2}+\sqrt{\frac{1}{2}}+\sqrt{72}-\sqrt{\frac{3}{2}}\)
f)\(\sqrt{2}\sqrt{2+\sqrt{3}}-2\left(\sqrt{3}-1\right)\)
g)\(\sqrt{5-2\sqrt{6}}+\sqrt{5+2\sqrt{6}}-\left(2\sqrt{3}-2007\right)\)
Thực hiện phép tính :
1 ) \(\frac{1}{5+2\sqrt{6}}\)\(+\)\(\frac{1}{5-2\sqrt{6}}\)
2 ) \(\frac{5+\sqrt{5}}{5-\sqrt{5}}\)\(+\)\(\frac{5-\sqrt{5}}{5+\sqrt{5}}\)
3 ) \(\frac{1}{2\sqrt{5}+3\sqrt{2}}\)\(-\)\(\frac{1}{2\sqrt{5}-3\sqrt{2}}\)
4 ) \(\frac{1}{3\sqrt{2}-4}\)\(-\)\(\frac{1}{3\sqrt{2}+4}\)
5 ) \(\frac{1}{\sqrt{7-\sqrt{24}}+1}\)\(-\)\(\frac{1}{\sqrt{7-\sqrt{24}}-1}\)
6 ) \(\frac{\sqrt{3}}{\sqrt{\sqrt{3}+1}-1}\)\(-\)\(\frac{1}{\sqrt{\sqrt{3}+1}+1}\)
7 ) \(\sqrt{\frac{3+\sqrt{5}}{3-\sqrt{5}}}\)\(+\)\(\sqrt{\frac{3-\sqrt{5}}{3+\sqrt{5}}}\)
8 ) \(\sqrt{\frac{5+2\sqrt{6}}{5-2\sqrt{6}}}\)\(+\)\(\sqrt{\frac{5-2\sqrt{6}}{5+2\sqrt{6}}}\)
rút gọn biểu thức
a) \(5\sqrt{\frac{1}{5}}+\frac{1}{3}\sqrt{45}+\frac{5-\sqrt{5}}{\sqrt{5}}\)
b) \(\sqrt{48}-6\sqrt{\frac{1}{3}}+\frac{\sqrt{3}-3}{\sqrt{3}}\)
c) \(\left(\frac{\sqrt{6}-\sqrt{2}}{1-\sqrt{3}}-\frac{5}{\sqrt{5}}\right):\left(\frac{1}{\sqrt{5}-\sqrt{2}}\right)\)
giải phương trinh
a) \(\sqrt{4x+4}-\sqrt{9x-9}-8\sqrt{\frac{x +1}{16}}=5\)
các bạn help mik với
Thực hiện các phép tính sau:
a) \(\frac{\sqrt{7}-5}{2}-\frac{6-2\sqrt{7}}{4}+\frac{6}{\sqrt{7}-2}-\frac{5}{4+\sqrt{7}}\)
b) \(\frac{1}{\sqrt{3}+\sqrt{2}-\sqrt{5}}-\frac{1}{\sqrt{3}+\sqrt{2}+\sqrt{5}}\)
c) \(\frac{1}{\sqrt{3}}+\frac{1}{3\sqrt{2}}+\frac{1}{\sqrt{3}}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}\)
Giúp em với mọi người ơi! Em đang rất cần!
Chứng minh rằng:
a)\(\left(\sqrt[3]{3+2\sqrt{2}}+\sqrt[3]{3-2\sqrt{2}}\right)^8>3^6\)
b) \(\sqrt[3]{\sqrt[5]{\frac{32}{5}}-\sqrt[5]{\frac{27}{5}}}=\sqrt[5]{\frac{1}{25}}+\sqrt[5]{\frac{3}{25}}-\sqrt[5]{\frac{9}{25}}\)