\(B=\dfrac{2^{10}\cdot13\cdot\left(1+5\right)}{2^8\cdot104}=\dfrac{2^2\cdot13}{104}\cdot6\)
\(=\dfrac{52}{104}\cdot6=6\cdot\dfrac{1}{2}=3\)
\(C=\dfrac{2^{10}\cdot3^8-2\cdot3^4\cdot2^4}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5}\)
\(=\dfrac{2^5\cdot3^4\left(2^5\cdot3^4-1\right)}{2^{10}\cdot3^8\cdot6}=\dfrac{1}{2^5}\cdot\dfrac{1}{3^4}\cdot\dfrac{2591}{6}\)
B=210⋅13⋅(1+5)28⋅104=22⋅13104⋅6B=210⋅13⋅(1+5)28⋅104=22⋅13104⋅6
=52104⋅6=6⋅12=3=52104⋅6=6⋅12=3
C=210⋅38−2⋅34⋅24210⋅38+28⋅38⋅22⋅5C=210⋅38−2⋅34⋅24210⋅38+28⋅38⋅22⋅5
=25⋅34(25⋅34−1)210⋅38⋅6=125⋅134⋅25916