BCNN(12,15)
12 = 22 . 3
15 = 3.5
=> BCNN(12,15) = 22 . 3 . 5 = 60
Ta có:
12 = 22 . 3
15 = 3 . 5
=> BCNN(12,15) = 22 . 3 . 5 = 12 . 5 = 60
Vậy: BCNN(12,15) = 60
BCNN(12,15)
12=2^2x3
15=3x5
BCNN(12,15)=2^2x3x5=60
Ta có :
12= 22 .3
15= 3.5
=> BCNN (12;15) = 22.3.5 = 60