không phân biệt được thầy hay cô lun :))
c: Ta có: \(3^6:3^2+2^3\cdot2^2-3^3\cdot3\)
\(=3^4-3^4+2^5\)
=32
d: Ta có: \(\left[600-\left(40:2^3+3\cdot5^3\right)\right]:5\)
\(=\left(600-5-375\right):5\)
\(=44\)
\(c.3^6:3^2+2^3.2^2-3^3.3\\ =3^4+2^5-3^4\\ =2^5=32\)
g: Ta có: \(100:\left\{250:\left[450-\left(4\cdot5^3-2^3\cdot25\right)\right]\right\}\)
\(=100:\left\{250:\left(450-300\right)\right\}\)
\(=100:\left(250:150\right)\)
\(=100:\dfrac{5}{3}=100\cdot\dfrac{3}{5}=60\)