\(H_2+Cl_2\rightarrow2HCl\left(1\right)\)
\(HCl+AgNO_3\rightarrow AgCl\downarrow+HNO_3\left(2\right)\)
\(n\left(H_2\right)=\dfrac{0,896}{24,79}=0,04\left(mol\right)\)
\(n\left(Cl_2\right)=\dfrac{0,672}{24,79}=0,03\left(mol\right)\)
\(n\left(H_2\right)>n\left(Cl_2\right)\) và dựa vào \(\left(1\right)\Rightarrow H_2\) dư
\(\left(1\right)\Rightarrow n\left(HCl\right)=0,03.2=0,06\left(mol\right)\)
\(n\left(AgCl\right)=\dfrac{m}{M}=\dfrac{0,7175}{108+35,5}=0,005\left(mol\right)\)
\(\left(2\right)\Rightarrow n\left(HCl\right)=1.0,005=0,005\left(mol\right)\)
Hiệu suất phản ứng tổng hợp \(HCl:\)
\(H\%=\dfrac{n\left(HCl\right)thực.tế}{n\left(HCl\right)lý,thuyết}.100\%=\dfrac{0,005}{0,06}.100\%\sim8,33\%\)