a, 2^x=8^4/16^3
<=> 2^x = (2^3)^4 / (2^4)^3
<=> 2^x = 2^12 / 2^12
<=> 2^x = 1
<=> 2^x = 2^0
<=> x = 0
Vậy x = 0
b,2^x=2^6/4^3
<=> 2^x = 2^6 / (2^2)^3
<=> 2^x = 2^6 / 2^6
<=> 2^x = 1
<=> 2^x = 2^0
<=> x = 0
Vậy x = 0
a, 2^x=8^4/16^3
<=> 2^x = (2^3)^4 / (2^4)^3
<=> 2^x = 2^12 / 2^12
<=> 2^x = 1
<=> 2^x = 2^0
<=> x = 0
Vậy x = 0
b,2^x=2^6/4^3
<=> 2^x = 2^6 / (2^2)^3
<=> 2^x = 2^6 / 2^6
<=> 2^x = 1
<=> 2^x = 2^0
<=> x = 0
Vậy x = 0
tìm x :
a/ (1/3 + 1/6 ) . 2x + 2x+1 = 212 + 210
b/ (1/2 - 1/6 ) . 3x+4 - 4 . 3x = 316 - 4 . 313
c/ 3/2 . 4x + 5/3 . 4x+2 = 3/2 . 48 + 5/3 . 410
tìm x biết
1) x=-1/2 + 3/4 2) x - 1/5 = 2/11 3) x - 5/6 = 16/42 + -8/56
4) x/5 = 5/6 + -19/30 5) |x| - 1/4 = 6/18 6)x = -1/2 +3/4
7) x/15 = 3/5 + -2/3 8)11/8 + 13/6 = 85/x 9) x - 7/8 = 13/12
10) x - -6/15 = 4/27 11) -\(\dfrac{-6}{12}\)+ x = 9/48 12) x - 4/6 = 5/25 + -7/15
Bài1: Tìm x biết:
a) 12 : 5 = x : 1,5
b) x/5 = 3/20
c) 4/x = 10/9
d) x/15 = 60/x
Bài 2:Cho x/3=y/5=z/6, tìm x,y,z biết
a) x + y -z=8
b)x-y+z=(-4)
c)x-2y+3z= (-33)
d) x^2 - 4y^2 + 2z^2 = (-475)
Tìm x
\(a,3-x=x+1,8\)
\(b,2x-5=7x+35\)
\(c,2\left(x+10\right)=3\left(x-6\right)\)
\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)
\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)
\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)
\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)
\(k,7x^2-11=6x^2-2\)
\(m,5\left(x+3.2^3\right)=10^2\)
\(n,\dfrac{4}{9}-(\dfrac{1}{6^2})=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)
Tìm x biết:
a) 6* 8^x-1 + 8^x+1 = 6* 8^19 + 8^21
b) 4* 3^x-1 + 2* 3^x+2 = 4* 3^6 +2* 3^9
\(b) 5^{x+4} - 3 . 5^{x+3} = 2. 5^{11} \)
\(c) 2 . 3^{x+2} + 4 . 3^{x+1} = 10 . 3 ^{6}\)
\(d) 6 . 8 ^ {x-1} + 8 ^ {x+1} = 6 . 8^ {19} + 8 ^ {21}\)
bài 2 . thực hiện phép tính
a. -1,75-(-1/9-2 1/18)
b. -1/12- (2 5/8-1/3)
c. -5/6-(-3/8+1/10)
Bài 3 :tìm x ,biết :
a. 11/13-(5/42-x)=(-15/28-11/13)
b. x+1/3=2/5-(-1/3)
c. 3/7-x=1/4-(-3/5)
Tìm x biết :
\(a,2^x=\frac{8^4}{16^3}\)
\(b,\left(-2\right)^x=-4^6-8^5\)
\(c,4^x=4.4^{10}-3.4^{10}\)
\(d,4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(e,\left(\frac{1}{3}+\frac{1}{6}\right).2^x+2^{x+1}=2^{12}+2^{10}\)
Ai nhanh mk sẽ tik nha , cám ơn m.n nhiều lắm
a,5^x+4-3×5^x+3=2×5^11
b,3×5^x+2+4×5^x-3=19×5^10
c,6×8^x-1+8^x-1=6×8^19+8^21
d,5×2^x+3×2^x+2=5×2^5+3×2^7