a, \(x^2-6x+9=4< =>\left(x-3\right)^2=4< =>\orbr{\begin{cases}x-3=2\\x-3=-2\end{cases}}\)
\(< =>\orbr{\begin{cases}x=5\\x=1\end{cases}}\)
b,\(x^2\left(x-3\right)-4\left(x-3\right)=0< =>\left(x-2\right)\left(x+2\right)\left(x-3\right)=0\)
\(< =>\orbr{\begin{cases}x=2\\x=-2\end{cases}orx=3}\)
c nhường mấy bn khácccc
a) x^2-6x+9=4.
x=1, x=5
b) x^2(x-3)-(4X-12)=0
x=-2, x=2, x=3
c) (2x+3)^2-4(x+2)^2=12
x=-19/4
a, \(x^2-6x+9=4\Leftrightarrow\left(x-3\right)^2=4=2^2\)
TH1 : \(x-3=2\Leftrightarrow x=5\)
TH2 : \(x-3=-2\Leftrightarrow x=1\)
b, \(x^2\left(x-3\right)-\left(4x-12\right)=0\Leftrightarrow\left(x-2\right)\left(x+2\right)\left(x-3\right)=0\Leftrightarrow x=\pm2;x=3\)
c, \(\left(2x+3\right)^2-4\left(x+2\right)^2=12\)
\(\Leftrightarrow4x^2+12x+9-4\left(x^2+4x+4\right)=12\Leftrightarrow-4x-7=12\Leftrightarrow x=-\frac{19}{4}\)
c) (2x+3)^2-4(x+2)^2=12
=> ( 2x + 3 - 2x - 4 )( 2x + 3 + 2x + 4 )=12
=> -1( 4x + 7 )=12
=> - 4x - 7 =12
=> 4x = -19
=> x = -19/4
