Question

Bài tập 8: Tìm x biết

Answer 1

a, \(x+\dfrac{5}{2}=-\dfrac{3}{2}\Leftrightarrow x=-\dfrac{3}{2}-\dfrac{5}{2}=-\dfrac{8}{2}=-4\)

b, \(x-\dfrac{3}{4}=\dfrac{7}{6}\Leftrightarrow x=\dfrac{7}{6}+\dfrac{3}{4}=\dfrac{28+18}{24}=\dfrac{23}{12}\)

c, \(\dfrac{5}{4}+x=\dfrac{2}{3}\Leftrightarrow x=\dfrac{2}{3}-\dfrac{5}{4}=\dfrac{8-15}{12}=-\dfrac{7}{12}\)

d, \(x-\dfrac{4}{7}=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}+\dfrac{4}{7}=\dfrac{21+16}{28}=\dfrac{37}{28}\)

e, \(\dfrac{1}{2}+x=\dfrac{5}{3}\Leftrightarrow x=\dfrac{5}{3}-\dfrac{1}{2}=\dfrac{10-3}{6}=\dfrac{7}{6}\)

f, \(\dfrac{4}{5}-x=\dfrac{3}{2}\Leftrightarrow x=\dfrac{4}{5}-\dfrac{3}{2}=\dfrac{8-15}{10}=-\dfrac{7}{10}\)

g, \(x+\dfrac{5}{6}=-\dfrac{1}{12}\Leftrightarrow x=-\dfrac{1}{12}-\dfrac{5}{6}=-\dfrac{1}{12}-\dfrac{10}{12}=-\dfrac{11}{12}\)

h, \(\dfrac{3}{4}-x=-\dfrac{7}{5}\Leftrightarrow x=\dfrac{3}{4}+\dfrac{7}{5}=\dfrac{15+28}{20}=\dfrac{43}{20}\)