Bạn coi lại đề câu a, chỗ \(\log_5-x\) đó
b.
\(\Leftrightarrow9^x-3^x-2.3^x-2=0\)
\(\Leftrightarrow3^x\left(3^x-1\right)-2\left(3^x-1\right)=0\)
\(\Leftrightarrow\left(3^x-2\right)\left(3^x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3^x=2\\3^x=1\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\log_32\\x=0\end{matrix}\right.\)