c, \(x-\dfrac{1}{5}=-\dfrac{3}{2}-\dfrac{1}{5}\Leftrightarrow x-\dfrac{1}{5}+\dfrac{1}{5}=-\dfrac{3}{2}\Leftrightarrow x=-\dfrac{3}{2}\)
d, \(x-\dfrac{1}{7}=-\dfrac{4}{3}-\dfrac{1}{7}\Leftrightarrow x-\dfrac{1}{7}+\dfrac{1}{7}=-\dfrac{4}{3}\Leftrightarrow x=-\dfrac{4}{3}\)