\(b.\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=\dfrac{7}{5}+\dfrac{7x}{10}\)
Ta có x chung nên ta có:
\(\dfrac{x}{2}-\left(\dfrac{3}{5}-\dfrac{13}{5}\right)=\dfrac{7}{5}+\dfrac{7}{10}\)
\(\dfrac{x}{2}-\left(-2\right)=\dfrac{21}{10}\)
\(\dfrac{x}{2}=\dfrac{21}{10}+\left(-2\right)\)
\(\dfrac{x}{2}=\dfrac{21}{10}+\dfrac{-20}{10}\)
\(\dfrac{x}{2}=\dfrac{1}{10}\)
\(\dfrac{5x}{10}=\dfrac{1}{10}\)
\(5x=1\)
\(x=\dfrac{1}{5}\)
x = 0.2
Vậy x=0.2