Ta co x/2 = y/5 =>x=(2y)/5 (1)
Lai co xy =10 (2)
Thay (1) vao (2) ta duoc (2y)/5.y=10=>(2y2)/5=10=>y2=10.(5/2)=>y2=25=>y=5 va y=-5
Khi y=5 thi x =10:5=2
Khi y=-5 thi x = 10 : (-5)=-2 quên tìm x h bổ sung :) -...-
\(\frac{x}{2}=\frac{y}{5}\)
\(\Rightarrow\frac{x}{2}.\frac{y}{5}=\frac{x}{2}^2\)
\(\Rightarrow1=\frac{x}{2}^2\)
\(\Rightarrow\frac{x}{2}=1\)
\(\Rightarrow x=2\)
\(\Rightarrow y=5\)
Vậy, x = 2; y = 5
\(\frac{x}{2}=\frac{y}{5}\)
Đặt \(\frac{x}{2}=\frac{y}{5}=k\)
\(\Rightarrow x=2k;y=5k\)
Ta có : \(x.y=10\)
\(\Rightarrow2k.5k=10\)
\(\Rightarrow k^2.10=10\)
\(\Rightarrow k^2=1\)
\(\Rightarrow k=1\)
\(\Leftrightarrow\hept{\begin{cases}x=2k=1\\y=5x=1\end{cases}\Rightarrow\hept{\begin{cases}x=2\\y=5\end{cases}}.}\)