Theo đề, ta có:
\(\left\{{}\begin{matrix}5a=4b\\\dfrac{a+15}{b+15}=\dfrac{9}{11}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5a-4b=0\\11a-9b=-30\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}55a-44b=0\\55a-45b=-150\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}b=150\\a=120\end{matrix}\right.\)