c: \(\Leftrightarrow\left(x-5\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)
Giải các phương trình tích sau:
1.a)(3x – 2)(4x + 5) = 0 b) (2,3x – 6,9)(0,1x + 2) = 0
c)(4x + 2)(x2 + 1) = 0 d) (2x + 7)(x – 5)(5x + 1) = 0
2. a)(3x + 2)(x2 – 1) = (9x2 – 4)(x + 1)
b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c)2x(x – 3) + 5(x – 3) = 0 d)(3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
3.a)(2x – 5)2 – (x + 2)2 = 0 b)(3x2 + 10x – 8)2 = (5x2 – 2x + 10)2
c)(x2 – 2x + 1) – 4 = 0 d)4x2 + 4x + 1 = x2
4. a) 3x2 + 2x – 1 = 0 b) x2 – 5x + 6 = 0
c) x2 – 3x + 2 = 0 d) 2x2 – 6x + 1 = 0
e) 4x2 – 12x + 5 = 0 f) 2x2 + 5x + 3 = 0
a, (3x-2) (x+6) (x^2 +5) = 0
b, (2x+5)^2 = (3x-1)^2
c, 4x^2 (x-1) - x+1 = 0
d, 9 (2x+1) = 4(x-5)^2
e, x^3 - 4x^2 - 12x +27 = 0
f, x^3 + 3x^2 -6x -8 =0
tim x
a)4x(x-7)-4x2=56
b)12x(3x-2)-(4-6x)=0
c)4(x-5)-(5-x)2=0
Tìm x
a. x2 - 12x - 2x + 24 = 0
b. x2 - 5x - 24 = 0
c. 4x2 - 12x - 7 = 0
d. x3 + 6x2 + 12x + 8 = 0
e. (x + 2)2 - x2 + 4 = 0
f. 2(x + 5) = x2 + 5x
m. 16(2x - 3)2 - 25(x - 5)2 = 0
n. x2 - 6x + 4 = 0
Tìm x
a. x2 - 12x - 2x + 24 = 0
b. x2 - 5x - 24 = 0
c. 4x2 - 12x - 7 = 0
d. x3 + 6x2 + 12x + 8 = 0
e. (x + 2)2 - x2 + 4 = 0
f. 2(x + 5) = x2 + 5x
m. 16(2x - 3)2 - 25(x - 5)2 = 0
n. x2 - 6x + 4 = 0
Tìm x
a. x2 - 12x - 2x + 24 = 0
b. x2 - 5x - 24 = 0
c. 4x2 - 12x - 7 = 0
d. x3 + 6x2 + 12x + 8 = 0
e. (x + 2)2 - x2 + 4 = 0
f. 2(x + 5) = x2 + 5x
m. 16(2x - 3)2 - 25(x - 5)2 = 0
n. x2 - 6x + 4 = 0
I) THỰC HIỆN PHÉP TÍNH a) 2x(x^2-4y) b)3x^2(x+3y) c) -1/2x^2(x-3) d) (x+6)(2x-7)+x e) (x-5)(2x+3)+x II phân tích đa thức thành nhân tử a) 6x^2+3xy b) 8x^2-10xy c) 3x(x-1)-y(1-x) d) x^2-2xy+y^2-64 e) 2x^2+3x-5 f) 16x-5x^2-3 g) x^2-5x-6 IIITÌM X BIẾT a)2x+1=0 b) -3x-5=0 c) -6x+7=0 d)(x+6)(2x+1)=0 e)2x^2+7x+3=0 f) (2x-3)(2x+1)=0 g) 2x(x-5)-x(3+2x)=26 h) 5x(x-1)=x-1 IV TÌM GTNN,GTLN. a) tìm giá trị nhỏ nhất x^2-6x+10 2x^2-6x b) tìm giá trị lớn nhất 4x-x^2-5 4x-x^2+3
Tìm x
a,(x2-4x+16)+(x+4)-x*(x+1)*(x+2)+3x2=0
b,(8x+2)*(1-3x)+(6x-1)*(4x-10)=-50
c,(x2+2x+4)*(2-x)+x*(x-3*(x+4))-x2+24=0
d,(x/2+3)*(5-6x)+(12x-2)*(x/4+3)=0
Tìm x, biết
a) 3x3-6x2=0
b) x(x-4)-12x+48=0
c) x(x-4) - (x2-8)
d) 2x(x-5) -x(2x+3)=16
e)(4x2-1) - (x-1)2 = -3
