Question

Bài 37 : Tìm giá trị của biểu thức sau                                                                              

Answer 1

a)\(\dfrac{4^2.4^3}{2^{10}}=\dfrac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\dfrac{2^4.2^6}{2^{10}}=1\)

b)\(\dfrac{\left(0,6\right)^5}{\left(0,2\right)^6}=\dfrac{\left(0,2\right)^5.3^5}{\left(0,2\right)^5.0,2}=\dfrac{3^5}{0,2}=1215\)

c)\(\dfrac{2^7.9^3}{6^5.8^2}=\dfrac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\dfrac{2^7.3^6}{2^5.3^5.2^6}=\dfrac{3}{2^4}=\dfrac{3}{16}\)

d)\(\dfrac{6^3+3.6^2+3^3}{-13}\)=\(\dfrac{2^3.3^3+3.2^2.3^2+3^3}{-13}=\dfrac{3^3.\left(2^3+2^2+1\right)}{-13}=\dfrac{3^3.13}{-13}=-3^3=-27\)

Answer 2

a) 1

b) 1215

c) 0,1875

d) -27