Bài 3 :
a) \(\left(\frac{1}{25}-0,6\right)^2:\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right)\cdot2\frac{2}{17}\right]\)
\(=\left(\frac{1}{25}-\frac{3}{5}\right)^2\cdot\frac{125}{49}+\left[\left(\frac{13}{4}-\frac{59}{9}\right)\cdot\frac{36}{17}\right]\)
\(=\left(-\frac{14}{25}\right)^2\cdot\frac{125}{49}+\left[\left(-\frac{119}{36}\right)\cdot\frac{36}{17}\right]\)
\(=-\frac{196}{625}\cdot\frac{125}{49}+\left(-7\right)=-\frac{4}{5}+\left(-7\right)=-\frac{39}{5}\)
Trả lời :
\(\left(\frac{1}{25}-0,6\right)^2\div\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right)\times2\frac{2}{17}\right]\)
\(=\left(\frac{1}{25}-\frac{3}{5}\right)^2\div\frac{49}{125}+\left[\frac{-119}{36}\times\frac{36}{17}\right]\)
\(=\left(\frac{-14}{25}\right)^2\div\frac{49}{125}-7\)
\(=\frac{4}{5}-7\)
\(=\frac{-31}{5}\)
\(\left(\frac{1}{25}-0,6\right)^2:\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right).2\frac{2}{17}\right]\)
\(=\left(-\frac{14}{25}\right)^2.\frac{125}{49}+\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)
\(=\frac{196}{625}.\frac{125}{49}+\left(-\frac{119}{36}.\frac{36}{17}\right)\)
\(=\frac{4}{5}+\left(-7\right)\)
\(=-\frac{31}{5}\)
Bỏ dấu " - " chỗ \(-\frac{196}{625}\)đi nhé,mình nhầm
Rồi khúc cuối là bạn ghi là \(\frac{4}{5}+\left(-7\right)=-\frac{31}{5}\)nhé,mình nhầm kết quả
\(=\left(\frac{1}{25}-0,6\right)^2:\frac{49}{125}+\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)
\(=\left(-\frac{14}{25}\right)^2:\frac{49}{125}+\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)
\(=\frac{196}{625}:\frac{49}{125}+\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)
\(=\frac{196}{625}:\frac{49}{125}+\left[-\frac{119}{36}.\frac{36}{17}\right]\)
\(=\frac{196}{625}:\frac{49}{125}+-7\)
\(=\frac{4}{5}+-7\)
\(=-\frac{31}{5}\)
