Bài 2:
a: Ta có: \(A=\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{1}{1-\sqrt{x}}\)
\(=\dfrac{x+2+x-1+x+\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}\)
\(=\dfrac{3x+\sqrt{x}+2}{x\sqrt{x}-1}\)
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