a, => 9 = 5.x - 3.x = 2.x
=> x = 9 :2 = 4,5
b, => 4 = x + x + 16
=> 4 = 2x+16
=> 2x = 4 - 16 = -12
=> x = -12 : 2 = -6
Tk mk nha
5x - 9 = 3x \(\Rightarrow\)5x - 3x = 9 \(\Rightarrow\)2x = 9 \(\Rightarrow\)\(x=\frac{9}{2}\)
4 - ( 16 + x ) = x \(\Rightarrow\)4 - 16 - x = x \(\Rightarrow\)2x = -12 \(\Rightarrow\)x = -6
a)5x-9=3x
\(\Rightarrow5x-3x=9\)
\(\Rightarrow2x=9\)
\(\Rightarrow x=\frac{9}{2}\)
Mà x\(\in\)Z nên k có giá trị nào của x
b)4-(16+x)=x
\(\Rightarrow4-16-x=x\)
\(\Rightarrow4-16=x+x\)
\(\Rightarrow-12=2x\)
\(\Rightarrow\frac{-12}{2}=x\)
\(\Rightarrow-6=x\)
Vậy x=-6