1,
(x-2)3+6.(x+1)2-x3
=(x-2)3-x3+6.(x2+2x+1)
\(=\left(x-2-x\right)\left[\left(x-2\right)^2+\left(x-2\right)x+x^2\right]+6\left(x^2+2x+1\right)\)
=(-2)(x2-4x+4 +x2-2x+x2)+ 6(x2+2x+1)
=(-2)(3x2-2x+4)+6(x2+2x+1)=-6x2+4x-8+6x2+12x+6
=16x-2
2, 2x(2x-1)2-3x(x+3).(x-3)-4x(x+1)2
=2x(4x2-4x+1)-3x.(x2-32)-4x(x2+2x+1)
=8x3-8x2+2x-3x3+27x-4x3-8x2-4x
=x3-16x2+25x
3,(x-2)3-x(x+1)+6x(x-3)
=x3-3.x22+3.x.22-23 -x2-x+6x2 -18x
=x3 -6x2+12x-8- x2-x+6x2-18x
=x3 -8- x2-x-18x+12x=x3-8-7x-x2