Question

Bài 1, Phân tích đa thức thành phân tử

1, a.(b+c) + 3b + 3c

Answer 1

A(B+C)+3(B+C)=(B+C)(A+3)

Answer 2

\(a\left(b+c\right)+3b+3c\)

\(\Rightarrow a\left(b+c\right)+3\left(b+c\right)\)

\(\Rightarrow\left(a+3\right)\left(b+c\right)\)

Answer 3

Ta có : a(b+c)+3b+3c=ab+ac+3b+3c=(ab+3b)+(ac+3c)=b(a+3)+c(a+3)=(a+3)(a+c)

Answer 4

\(a.\left(b+c\right)+3b+3c\)

\(=a.\left(b+c\right)+3.\left(b+c\right)\)

\(=\left(b+c\right).\left(a+3\right)\)