Ta có: \(M_A=8,5.2=17\left(g/mol\right)\)
Gọi \(\left\{{}\begin{matrix}n_{H_2}=a\left(mol\right)\\n_{O_2}=b\left(mol\right)\end{matrix}\right.\)
`=>` \(\left\{{}\begin{matrix}n_A=a+b\left(mol\right)\\m_A=2a+32b\left(g\right)\end{matrix}\right.\)
`=>` \(M_A=\dfrac{m_A}{n_A}=\dfrac{2a+32a}{a+b}=17\left(g/mol\right)\)
`=>` \(2a+32b=17a+17b\)
`=>` \(15b=15a\)
`=>` \(\dfrac{a}{b}=\dfrac{15}{15}=\dfrac{1}{1}\Leftrightarrow a=b\)
`=>` \(\left\{{}\begin{matrix}\%V_{H_2}=\%n_{H_2}=\dfrac{a}{a+b}.100\%=\dfrac{a}{a+a}.100\%=50\%\\\%V_{O_2}=100\%-50\%=50\%\end{matrix}\right.\)
`=>` \(\left\{{}\begin{matrix}\%m_{H_2}=\dfrac{2a}{2a+32b}=\dfrac{2a}{2a+32a}.100\%=5,88\%\\\%m_{O_2}=100\%-5,88\%=94,12\%\end{matrix}\right.\)
