5*4/4x+yx/4x=1/8
20+yx/4x=1/8
(20+yx)*8=4x
160+8yx=4x
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Bai 1:a)Tim x biet\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\times\left(x+1\right)}=\frac{2009}{2011}\)
b)\(\left(x-1\right)\times f\left(x\right)=\left(x+4\right)\times f\left(x\right)\)voi moi x
Bai 2;Tim x;y;z biet a)\(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}\) b)\(\frac{2x+1}{5}=\frac{3y-z}{7}=\frac{2x+3y-1}{6x}\)
Tim x biet Bai 1: Tim cap so (x,y) biet: frac{1+3y}{12}frac{1+5y}{5x}frac{1+7y}{4x}Bai 2; Cho frac{a}{b}frac{b}{c}frac{c}{a}va a,b,c khac ; a2012. tinh b,cBai 3: tim cac so x,y,z biet :frac{y+x+1}{x}frac{x+z+2}{y}frac{x+y-3}{z}frac{1}{x+y+z}Bai 4: Tim x, biet rang:frac{1+2y}{18}frac{1+4y}{24}frac{1+6y}{6x} giup minh di minh dang rat gap cam on
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Tim x biet
Bai 1: Tim cap so (x,y) biet: \(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
Bai 2; Cho \(\frac{a}{b}\)=\(\frac{b}{c}\)=\(\frac{c}{a}\)va a,b,c khac ; a=2012. tinh b,c
Bai 3: tim cac so x,y,z biet :
\(\frac{y+x+1}{x}\)=\(\frac{x+z+2}{y}\)=\(\frac{x+y-3}{z}\)=\(\frac{1}{x+y+z}\)
Bai 4: Tim x, biet rang:\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
giup minh di minh dang rat gap cam on
bai 1: Tim x biet
\(\hept{\begin{cases}x-y=\frac{3}{10}\\y\left(x-y\right)=-\frac{3}{50}\end{cases}}\)
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x+\(\left(-\frac{31}{12}\right)^2\)=\(\left(\frac{49}{12}\right)^2\)-x=y2
Bai 9: Tim x,y,z biet:
(x-1)2+(x+y)2+(xy-z)2=0
1. tìm x, ya, x - y +2xy 7b, xy + 3x -y 6c, frac{1}{x}+ frac{1}{y}frac{1}{5}d, (6 sqrt{x-1}) ⋮( 2sqrt{x-3})4. tìm x inza, A frac{1-2x}{x+3}inzb, B frac{2012sqrt{x+5}}{1006sqrt{x+1}}inzHELP ME ........!!!!!!!!!
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1. tìm x, y
a, x - y +2xy =7
b, xy + 3x -y = 6
c, \(\frac{1}{x}\)+ \(\frac{1}{y}\)=\(\frac{1}{5}\)
d, (6 \(\sqrt{x-1}\)) \(⋮\)( 2\(\sqrt{x-3}\))
4. tìm x \(\in\)z
a, A =\(\frac{1-2x}{x+3}\)\(\in\)z
b, B = \(\frac{2012\sqrt{x+5}}{1006\sqrt{x+1}}\)\(\in\)z
HELP ME ........!!!!!!!!!
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}vax-2y+3z=14\)
de bai la tim x, y, z biet
giup mk
mk tk
mk dag voi
Tim x,y,z biet:
a, xy=z ; yz=4x ; zx=9x
b, \(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
Tim x,y,z biet:
a, \(xy=z;yz=4x;zx=9y\)
b, \(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
Tìm x thuộc Z
a, \(\frac{\sqrt{x}-3}{\sqrt{x}+1}\)
b, \(\frac{2\left(\sqrt{2}-5\right)}{\sqrt{x}+1}\in Z\)
c, \(\frac{2\sqrt{x}+1}{3\sqrt{x}-1}\in Z\)
d, \(\frac{\sqrt{x}-2}{\sqrt{x}+2}\in Z\)
Tim ba so x, y, z biet \(\frac{y+z+1}{x}=\frac{x+ z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)