Question

Bài 1:

a) Không quy đồng hãy so sánh:                  b) Tính nhanh:

\(\dfrac{2003}{2001}\) và \(\dfrac{1999}{1997}\)                                           \(\dfrac{5}{9}\) x \(\dfrac{1}{4}\) +\(\dfrac{4}{9}\) x\(\dfrac{3}{12}\)

 

 

Answer 1

2003 / 2001 = 1 + 2/2001

1999/1997 = 1 + 2/1997 

vì 2/ 2001 < 2/1997

nên 1 + 2/2001 < 1 + 2/1997

hay 2003 < 1999/1997

b, = 5/9 x 1/4 + 4/9 x 1/4 

= 1/4 x ( 5/9 + 4/9 )

= 1/4 x 1 

= 1/4

Answer 2

* Ý a mk k nhớ cách làm ^^, xl * 

\(b,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}\)

\(=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}\)

\(=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{5}{9}\right)\)

\(=\dfrac{1}{4}\times\dfrac{9}{9}=\dfrac{1}{4}\times1=\dfrac{1}{4}\)

Answer 3

Giúp mình, mình đang cần gấp!!!

 

Answer 4

\(a,\dfrac{2003}{2001}< \dfrac{1999}{1997}\)

b,=(5/9 + 4/9) * 1/4

   =1 * 1/4 

   =1/4

Answer 5

thật á?

Answer 6

a) \(1-\dfrac{2003}{2001}=\dfrac{2}{2001}\)

\(1-\dfrac{1999}{1997}=\dfrac{2}{1997}\)

\(Vì\) \(\dfrac{2}{1997}>\dfrac{2}{2001}\)

⇒ \(\dfrac{2003}{2001}< \dfrac{1999}{1997}\)

Answer 7

b) \(\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}\)

\(=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}\)

\(=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\)

\(=\dfrac{1}{4}\times\dfrac{9}{9}=\dfrac{1}{4}\)