2B = 3B - B = (33 + 34 + ... + 3101) - (32 + 33 + 34 +....+ 3100) = 3101 - 32
=> B = \(\frac{3^{101}-3^2}{2}\)
Ta có:
B x 3=33+34+35+.........+3101
2B=3B-B=(33+34+35+......+3101)-(32+33+34+........+3100)
=3101-32
B=3101-32/2
A = 3 + 32 + 33 + 34 +.............3100
3A =32 + 33 + 34 +.............3101
3A - A = (3 + 32 + 33 + 34 +.............3100) - (32 + 33 + 34 +.............3101)
2A = 3101 - 3
\(A=\frac{3^{101}-3}{2}\)