Các câu hỏi tương tự
1) √(2x-1) <= 8-2x
2) √[(x+1)(4-x)] > x-2
3) √(x-2x^2+1) > 1-x
4) √(x+5) - √(x+4) > √(x+3)
5) √(5x-1) - √(x-1) > √(2x-4)
6) √(x+3) >= √(2x-8) + √(7-x)
7) √(x+2) - √(3-x) < √(5-2x)
8) √(x+1) > 3 - √(x+4)
9) √(5x-1) - √(4x-1)<= 3√x
10) { {√[2(x^2-16)]} / √(x-3) }+ √(x-3) > (7-x) / √(x-3)
Giúp mình 10 câu này với ạaa
1 a..Rút gọn biểu thức A = \(\dfrac{\text{ x 2 − 4 x + 4}}{\text{x 3 − 2 x 2 − ( 4 x − 8 ) }}\)
b. Rút gọn biểu thức B = \(\left(\dfrac{x+2}{\text{x }\sqrt{\text{x }}+1}-\dfrac{1}{\sqrt{\text{x}}+1}\right).\dfrac{\text{4 }\sqrt{x}}{3}\)
B=\(\dfrac{2\left(x+4\right)}{x-3\sqrt{x}-4}+\dfrac{\sqrt{x}}{\sqrt{x}+1}-\dfrac{8}{\sqrt{x}-4}\) Với x≥0,x≠16
a)Rút gọn B
a. 3x⁴ - x² - 234 = 0 b. x/1-x = 2x+3/(x-1)(x+2) c. x²(x+1)-3x=3x²-2x-2 d. (x+4)(x+5)(x+7)(x+8)=4
giải pt
a 2(x+3)(x-4)=(2x-1)(x+2)-27
b (3x+2)(x-1)-3(x+1)(x-2)=4
c (x+2)(x^2 -2x+4)-x(x-3)(x+3)=26
d (3x+2)(3x-2)-(3x-4)^2=28
e 5(x+3)^2-5(x-4)(x+8)=3x
f 2x(x+2)^2-8x^2=2(x-2)(x^2+2x+4)
g (2x-1)(4x^2+2x+1)-4x(2x^2-3)=23
h x(x-2)(x+2)-(x-3)(x^2+3x+9)+1=0
i x(x^2+x+1)-(x-1)(x+1)x=x^2+2
1) x-\(7\sqrt{x-3}\) -9=0 2) \(\sqrt{x+3}\) =5-\(\sqrt{x-2}\) 3) \(\sqrt{x-4\sqrt{x+4}}\) =3 4) \(\sqrt{8-\dfrac{2}{3}x}-5\sqrt{2}\) =0 5) \(\sqrt{x^2-4x+4}\) =2-x
2) N=\(\left(\dfrac{x+2}{x\sqrt{x}+1}-\dfrac{1}{\sqrt{x}+1}\right).\dfrac{4\sqrt{x}}{3}\)
a) Rút gọn N ( đkxđ )
b) Tìm x để N= 8/9
c) Tìm x để \(\dfrac{1}{N}>\dfrac{3\sqrt{x}}{4}\)
a)x^8+X^4-2=0 b)3(X^2+x)^2-2(X^2+x)-1=0
√3x+1=2x
√3x^2-10x-44=8-x
√x+3 + √3x+1 =4
(x+3)+(x-√4-x^2)=0
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