\(a,\Leftrightarrow2x\left(4x^2-25\right)=0\\ \Leftrightarrow2x\left(2x-5\right)\left(2x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\\ b,\Leftrightarrow9\left(2x-1\right)^2-\left(x+3\right)^2=0\\ \Leftrightarrow\left(6x-3-x-3\right)\left(6x-3+x+3\right)=0\\ \Leftrightarrow7x\left(5x-6\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{6}{5}\end{matrix}\right.\\ c,\Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=1\end{matrix}\right.\)
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a) M = t(10 - 4t) - t2(2t - 5) – 2t + 5 tại t = 5 ;
